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When the temperature is increased, heat is supplied which increases the kinetic energy of the reacting molecules. This shall increase the number of collisions and ultimately the rate of reaction shall be enhanced. Arrhenius suggested a equation which describes K as a function of temperature, i.e. k=Ae^(-E_(a)//RT) where k= rate constant A= a constant (frequency factor) E_(a)= energy of activation log_(10)k=log_(10)A-(E_(a))/(2.303R)[(1)/(R )] Y=C+MX It is the equation of straight line with negative slope. On plotting log_(10)k against [(1)/(T)] we get a straight line as shown below : The slope gives activation energy and intercept gives frequency factor. Also log.(k_(2))/(k_(1))=(E_(a))/(2.303)[(T_(2)-T_(1))/(T_(1)T_(2))] The rate of chemical reaction doubles for every 10^(@)C rise in temperature . If the temperature is increasedby 60^(@)C, the rate of reaction increases by about

Answer»

`20` TIMES
`32` times
`164` times
`128` times

Answer :C


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