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When the temperature of a liquid is raised by 100^(@)C, 0.01% of the liquid is expelled. Calculate the coefficient of apparent expansion of the liquid. |
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> mass of the liquid `(m _(1) = <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> gm,` <br/> Mass of the expelled liquid `(m _(1) - m _(2)) = 0.01 gm (0.01%)` <br/> Remaining liquid `= m _(2) =<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>- -0.01 = 99.99 gm , t _(2) -t _(1) = 100^(@)C` <br/> From `gamma _(a) = (m _(1) - m _(2))/( m _(2) (t _(2) -t _(1)) ) = ( 0.01)/(99.99 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 100) = (1)/( 999900) = 0.00001//^(@)C` <br/> `thereore` <a href="https://interviewquestions.tuteehub.com/tag/coefficient-920926" style="font-weight:bold;" target="_blank" title="Click to know more about COEFFICIENT">COEFFICIENT</a> of apparent expansion of the liquid `= 10 xx 10 ^(-) //^(@)C`</body></html> | |