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When the temperature of a liquid is raised by 100^(@)C, 0.01% of the liquid is expelled. Calculate the coefficient of apparent expansion of the liquid. |
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Answer» Solution :INITIAL mass of the liquid `(m _(1) = 100 gm,` Mass of the expelled liquid `(m _(1) - m _(2)) = 0.01 gm (0.01%)` Remaining liquid `= m _(2) =10- -0.01 = 99.99 gm , t _(2) -t _(1) = 100^(@)C` From `gamma _(a) = (m _(1) - m _(2))/( m _(2) (t _(2) -t _(1)) ) = ( 0.01)/(99.99 XX 100) = (1)/( 999900) = 0.00001//^(@)C` `thereore` COEFFICIENT of apparent expansion of the liquid `= 10 xx 10 ^(-) //^(@)C` |
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