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When two capacitors are joined in series the resultance capacity is `2.4 muF` and when the same two are joined in parallel the resultant capacity is `10 mu F`. Their individual capacities are.A. `7 mu F,3 mu F`B. `1 mu F,9 mu F`C. `6 mu F,4 mu F`D. `8 mu F,2 mu F` |
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Answer» Correct Answer - C `C_(S)=(C_(1)C_(2))/(C_(1)+C_(2)) ,C_(1)+C_(2)=C_(P)`. |
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