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When water is electrolysed, hydrogen and oxygen gas are produced. If 1.008 g of `H_(2)` is liberated at the cathode. What mass of `O_(2)` is formed at the anode?A. 32gB. 16gC. 8gD. 4g |
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Answer» Correct Answer - C `(W_(1))/(W_(2)) = (E_(1))/(E_(2))` `(1.008)/(W_(2)) = (1.008)/(8)` `:. W_(2) = 8 g` Where, `E_(1) and E_(2)` are equivalent masses of hydrogen and oxygen respectively |
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