1.

When water is electrolysed, hydrogen and oxygen gas are produced. If 1.008 g of `H_(2)` is liberated at the cathode. What mass of `O_(2)` is formed at the anode?A. 32gB. 16gC. 8gD. 4g

Answer» Correct Answer - C
`(W_(1))/(W_(2)) = (E_(1))/(E_(2))`
`(1.008)/(W_(2)) = (1.008)/(8)`
`:. W_(2) = 8 g`
Where, `E_(1) and E_(2)` are equivalent masses of hydrogen and oxygen respectively


Discussion

No Comment Found

Related InterviewSolutions