When we analyse the projectile motion from any accelerated frame O as vecr_(o),vecu_(o) and veca_(o) respectively, express the following terms, vecr_(pO)+veca_(p)-vecr_(O),vecu_(pO)=vecu_(p)-vecu_(O) and veca_(pO)=veca_(p)-veca_(O) where P stands for projectile. Then using the following kinematical equations of the projectile (For constant acceleration) relative to the accelerating frame ,we have vecS_(pO)=vecu_(pO)t+1/2veca_(pO)t^(2),vecv_(pO) =vecu_(pO)+veca_(pO)t and v_(pO)^(2)=u_(pO)^(2)+2veca.vecs_pO Using the above expressions, anwer the following question:A projectile has initial velocity v_(0) realtive to the large plate which is moving with a constant upward acceleration a. Refering to Q.1, velocity of the projectile relative to B ofter some time

When we analyse the projectile motion from any accelerated frame O as

1.	When we analyse the projectile motion from any accelerated frame O as vecr_(o),vecu_(o) and veca_(o) respectively, express the following terms, vecr_(pO)+veca_(p)-vecr_(O),vecu_(pO)=vecu_(p)-vecu_(O) and veca_(pO)=veca_(p)-veca_(O) where P stands for projectile. Then using the following kinematical equations of the projectile (For constant acceleration) relative to the accelerating frame ,we have vecS_(pO)=vecu_(pO)t+1/2veca_(pO)t^(2),vecv_(pO) =vecu_(pO)+veca_(pO)t and v_(pO)^(2)=u_(pO)^(2)+2veca.vecs_pO Using the above expressions, anwer the following question:A projectile has initial velocity v_(0) realtive to the large plate which is moving with a constant upward acceleration a. Refering to Q.1, velocity of the projectile relative to B ofter some time
Answer» `ltv_(0) "atan angle" thetalttheta_(0)` `gtv_(0) "atan angle" thetagttheta_(0)` `gtv_(0) "atan angle" theta=theta_(0)` `v_(0) "atan angle" theta=theta_(0)` Solution :Here`B` is ground FRAME, w.r.t `B` projection velocity will be greater than `V_(0)`. Hence when `thetagttheta_(0)` projectile velocity will be greater than `V_(0)`.