1.

When we heat a gas sample from 27°C to 327°C. then the initial average kinetic energy, of the molecules was E. What will be the average kinetic energy after heating ?

Answer»

Doubled
Halved
Multiplied by the factor 327 `//` 27
Raised to the POWER two .

SOLUTION :K.E. is proportional to T so that
`( KE_(1))/( KE_(2)) = ( 300)/( 600)`
or `KE_(2) = 2KE_(1)`


Discussion

No Comment Found