1.

When would the be Broglie wavelength of a moving electron become equal to that of a moving proton? Mass of electron = 9.1095 xx 10^(-31)kg and mass of proton = 1.6725 xx 10^(-27) kg

Answer»

Solution :`lamda_(e) = (h)/(m_(e) v_(e)) , LAMDA _(p) = (h)/(m_(p) v_(p))`
When `lamda_(e) = lamda_(p), m_(e) v_(e) = m_(p) v_(p) or (v_(e))/(v_(p)) = (m_(p))/(m_(e)) = (1.6725 XX 10^(-27) kg)/(9.1095 xx 10^(-31)kg) = 1836`, i.e., `v_(e) = 1836 xx v_(p)`


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