Saved Bookmarks
| 1. |
When would the wavelength associated with an electron become equal to that with proton ? (Mass of electron = 9.10 xx 10^(-31) kg, Mass of proton =1.6725 xx 10^(-27)kg) |
|
Answer» Solution :Wave LENGTHS of electron and proton are `lambda_(c)=(h)/(m_(e)v_(e)).lambda_(p)=(h)/(m_(p)v_(p))" But "lambda_(e)=lambda_(p)` THEREFORE, `(h)/(m_(e)v_(e))=(h)/(m_(p)v_(p)) or m_(e)v_(e)=m_(p)v_(p)` `V_(e)=(m_(p)v_(p))/(m_(e))=(1.6727xx10^(-27)kg)/(9.10xx10^(-31)kg)xxv_(p)=1837v_(p)` `"Velocity of electron "=1837xx" velocity of proton."` |
|