1.

When zinc electrode and calomel electrode are coupled to form a cell , the cell emf is given as

Answer»

`E_(cell)^(0)=E_(Zn("ox"))-E_("Calomel"("RED"))^(0)`
`E_(cell)^(0)=E_("Calomel"("red"))^(0)-E_(Zn("ox"))^(0)`
`E_(cell)^(0)=E_("Calomel"("red"))^(0)-E_(Zn("ox"))^(0)`
`E_(cell)^(0)=E_(Zn("ox"))-E_("Calomel"("ox"))^(0)`

SOLUTION :`E_("Calomel(red)")^(0) GT E_(Zn("red"))^(0)`


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