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When1g liquidnaphthalene ( C_(10) H_(8)) solidifies.149 jouls of heat is evolved. Calculate the enthalpy of fusion of naphthalene. |
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Answer» Solution :Molar mass of NAPHTHALENE `(C_(10)H_(8))= 128 g mol^(-1)` When 1 g of liquidnaphthalene solidified, HEAT evolved `= 149 xx 128 ` joules `= 19072` Joules Since fuson is reverse of solidification, therefore, heat absorbed for FUSION of one mole of naphthalene `=` 19072 joules, i.e., Enthalpy of fusion `(Delta _(FUS) H )= + 19072` joules `//` mole |
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