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WhenCH_2 = CH -O - CH_2 - CH_3 reacts with one mole of HI , one of the products formed is |
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Answer» `0.693 xx 3 " M Min"^(-1)` `t_(1//2)= 10 ` min `K = (0.693)/10 = 0.693 "min"^(-1)` As `t_(1//2)` is 10 min , after 20 minutesthe concentrationwill be3 M . Hence, RATE` = 0.693 xx 3 " M " min^(-1)` |
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