Whenever a hydrogen atom emits a quantum in the visible region of Balm

1.	Whenever a hydrogen atom emits a quantum in the visible region of Balmer series :
Answer» it may emit another quantum in Balmer series again it must emit another quantum in ultraviolet region of LYMAN series second quatum of wavelength 122nm will be emitted second quantum will be emitted in Paschen series i.e., near infrared region Solution :Second quantum will be in Lyman series because from `2^(nd)` shell the ELECTRON will FALL to first shell or ground STATE. `1/(lambda) = R [(1)/(n_1^2) - 1/(n_2^2) ] = 109677 [1/(1^2) - 1/(2^2)]` `lambda = 122 xx 10^(-7) cm = 122 nm` After coming to `2^(nd)` orbit then electron can go `1^(st)` orbit. So lyman series is possible .

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