1.

WhenHg_(2)Cl_(2) ionizes, the ins produced and the unpaired electrons present on the cation respectivelyare

Answer»

`2HG^(+)` and `2Cl^(-)`, two
`Hg_(2)^(2+) ` and `2Cl^(-) `, two
`Hg_(2)^(2-)` and `2Cl^(-)` , one
`Hg_(2)^(2+)` and `2Cl^(-)`, zero

Solution :`Hg_(2)Cl_(2) rarr Hg_(2)^(2+) + 2Cl^(-) `. Each `HG^(+)` has one unpaired electron. HENCE, `Hg_(2)^(2+)` has no unpaired electron.


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