1.

WhenNH_(3) is treated with diborane at low temperature and then heated at 200^@C , the product formed is

Answer»

`B_(2) H_(6)`
`B_(2) N_(2) H_(6)`
`B_(3) N_(3) H_(6)`
`B_(2) H_(6) N_(2)`

SOLUTION :Ammonia is a lewis base, while diborane is a Lewis acid. Therefore at ROOM temperature they react with each other giving an addition product. Which on heating at `200^@C` gives a volatile compound KNOWN as borazole or inorganic benzene `(B_3N_3H_6)`
`B_2H_6 + 2NH_3 RARR B_2H_6 cdot 2NH_3`
`3(B_2H_6 cdot 2NH_3) overset(200^@C)(rarr) 2(B_3N_3H_6)+ 12H_2`


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