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Which amount of chlorine gas liberated at anode, if 1 ampere current is passed for 30 minutes from NaCI solution? (a) 0.66 moles (b) 0.33 moles (c) 0.66 g (d) 0.33 g |
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Answer» (c) 0.66 g 2Cl- → Cl2 + 2e- Q = It. Amount of current passed = 1 x 30 x 60 = 1800C The amount of Cl2 liberated by passing 1800 coulomb of electric charge = \(\frac{1\times1800\times71}{2\times96500}\) = 0.66g |
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