1.

Which CI_(2) is passed through hot NaOH solution, oxidation number of CI changes from E238

Answer»

`-1 to 0`
`0 to -1`
`0 to +5`
`0 to +7`

SOLUTION :` 3overset(0)CI_(2)+^NaOHrarr5Naoverset(-1)CI+Naoverset(+5)CIO_(3)+3h_(2)O`


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