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1. |
Which `CI_(2)` is passed through hot `NaOH` solution, oxidation number of CI changes from E238A. `-1 to 0`B. `0 to -1`C. `0 to +5`D. `0 to +7` |
Answer» Correct Answer - B::C ` 3overset(0)CI_(2)+^NaOHrarr5Naoverset(-1)CI+Naoverset(+5)CIO_(3)+3h_(2)O` |
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