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Which compound in each of the following pairs will react faster in S_(N)2 reactionwith ""^(Θ)OH ?(i) CH_(3)Br or CH_(3)I(ii) (CH_(3))_(3)C Cl or CH_(3)Cl |
Answer» Solution :(i) Due to large size of iodine, the C - I bond is a WEAK bond as compared to C - Br. Also, `I^(-)` is a better leaving group. So, `CH_(3) - I` will react with `""^(Θ)OH` via `S_(N)2` than `CH_(3)-Br`. (ii) In `S_(N)2` reaction, the nucleophile attacks from the opposite side of the leaving group. The attack is favoured if there is presence of small groups i.e., minimum steric HINDRANCE. Thus, `CH_(3)Cl` will react faster via `S_(N)2`. 
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