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Which compound in each of the following paris will react faster in `SN^(2)` reaction with `HO^(o-)` ? a. CH_(3)Br` or `CH_(3)I` b. `(CH_(3))_(3)CCl` or `CH_(3)Cl` c. `CH_(2) = CHBr` or `CH_(2) = CH - CH_(2)Br` |
Answer» `SN^(2)` reactivity: a. `CH_(3)I` (`I^(o-)` is a better leaving group than `Br^(o-)`) , b. `CH_(3)Cl (1^(@) RX)` c. `CH_(2) = CH - CH_(2)Br` (Allylic bromide) Vinyl bromide `(CH_(2) = CH - Br)` neither undergoes `SN^(1)` nor `SN^(2)`. |
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