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Which condition of Rolle's theorem is violated by the functionf(x) = sin x in [0,(3pi)/\4]

Answer»

SOLUTION :`f(0)=0,f((3PI)/4)=sin((3pi)/4)=1/sqrt2 `as `f(0)nef((3pi)/4)` The CONDITION f(a) = (B) is VIOLATED.


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