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Which equation shows the proper setup to find the volume of a 0.250 M CaCl2 solution that contains 39.5 g of CaCl2? mc001-1.jpg mc001-2.jpg mc001-3.jpg |
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Answer» We know that molarity is the no of moles per UNIT volume.From following relation we can calculate AMOUNT of cacl2 REQUIRED (X)to prepare 0.25 M cacl2 250 ml SOLUTION.1000ml—1M—111g cacl2250ml —0.25—X g cacl2So that from above1000ml ×1M×X g= 250ml×0.25M×111gX=[250ml×0.25M×111g]÷[1000ml×1M]X=6.9375 g of cacl2Hence by dissolving 6.9375 g of cacl2 in 250 ml volumetric flask with distilled water then you will get 0.25 M cacl2 solution. |
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