1.

Which has greater resistance : 1 kW electroheater or a 110 W filament bulb, both marked for 220V?

Answer» Resistance of heater, `R_(1) = V^(2)/P_(1) = (220)^(2)/1000 Omega`
Resistance of bulb, `R_(2) = V^(2)/P_(2) = (220)^(2)/100 Omega`
`R_(1)/R_(2) = 100/1000 = 1/10 or R_(2) = 10R_(1)`
Thus resistance of bulb is greater than heater.


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