1.

Which has maximum number of atoms?

Answer»

24 g of C
56 g of Fe(56)
27 g of Al(27)
108 of AG (108)

SOLUTION :24 g `C = 24/12` MOL `=2 mol = 2 xx N_(0)` atoms
56 g Fe `=56/56 mol = 1mol = N_(0)` atoms
27 g Al `=27/27 mol =1 mol = N_(0)` atoms
108 g Ag `=108/108 mol = 1 mol = N_(0)` atoms.


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