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Which has maximum number of molecules?A. `7 gN_(2)`B. `7 g H_(2)`C. `16 g NO_(2)`D. `16 g O_(2)` |
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Answer» Correct Answer - B In 7 g nitrogen , number of molecules `=(7.0)/(28) "mol"` `=0.25xxN_(A)` molecules where , `N_(A)=` Avogadro number `=6.023xx10^(23)` in 2 g of `H_(2)=(2.0)/(2)" mol" =1xxN_(A)` molecules in 16 g of `NO_(2)=(16.0)/(46)" mol" ` " " `0.348xxN_(A)`molecules In 16 g of `O_(2)=(16)/(32) " mol " =0.5xxN_(A)` molecules Hence , maximum number of molecules are present in 2 g of `H_(2)`. |
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