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Which has maximum number of molecules among the following? |
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Answer» 44 g of `CO_(2)` No. of moles of `O_(3)=((48G))/(("48 g mol"^(-1)))=1`mol No. of moles of `H_(2)=(8G)/(("2g mol"^(-1)))=4` mol No. of moles of `SO_(2)=((64G))/(("64g mol"^(-1)))=1` mol `:.` 4 moles or 8g of `H_(2)` have max. no of molecules. |
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