1.

Which has maximum number of molecules among the following?

Answer»

44 g of `CO_(2)`
48 g of `O_(3)`
8 g of `H_(2)`
64 g of `SO_(2)`

Solution :No. of MOLES of `CO_(2)=((44g))/(("44 g mol"^(-1)))=1` mol
No. of moles of `O_(3)=((48G))/(("48 g mol"^(-1)))=1`mol
No. of moles of `H_(2)=(8G)/(("2g mol"^(-1)))=4` mol
No. of moles of `SO_(2)=((64G))/(("64g mol"^(-1)))=1` mol
`:.` 4 moles or 8g of `H_(2)` have max. no of molecules.


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