1.

Which has maximum volume at S.T.P.?

Answer»

`1.5xx10^(23)` molecules of `CO_(2)`
1 g `H_(2)`
4 g `O_(2)`
16 g `SO_(3)`

Solution :(A) Volume of `CO_(2)` at S.T.P.
`= (22.4Lxx1.5xx10^(23))/(6.02xx10^(23))=5.6 L`
(B) Volume of 1 g of `H_(2)`(0.5 mol) at S.T.P.
`= (22.4L)/(2) = 11.2L`
(C) VOUME of 4 g of `O_(2)`(0.125 mol) at S.T.P. = 2.8 L
(D) Volume of 16 g of `SO_(3)`(0.2 mol) at S.T.P. = 4.48 L
(Molar mass of `H_(2), O_(2)` and `SO_(3)` are 32 g and 80 g `mol^(-1)` respectively)
Thus 1 g of `H_(2)` at S.T.P. has largest volume


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