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Which has more energy of election: (i) Last election of Cl− or 1/last electron of O2− (ii) n = 4,l = 3 or n = 5,l = 2 |
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Answer» Electronic Configuration: Cl− = 2, 8, 8 = 1s2 , 2s22p6 , 3s23p6 O2− = 2, 8 = 1s2 , 2s2sp6 Since last electron of Cl− occurs in 3p sub- shell and last electron of O2− occurs 2p subshell. As we know that, according to Aufbau principle, 3p Subshell has more energy than 2p subshell. Therefore, last electron of Cl− has more energy of electron. (ii) n = 4, l = 3 represent 4f n = 5, l = 2 represents 5p According to Aufbau principle, the energy of 4f is more than 5p. So, n = 4, l = 3 has more energy of electron. |
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