1.

Which has the maximum number of molecules among the following ?

Answer»

44 g of `CO_(2)`
48 g `O_(2)`
8 g `H_(2)`
64 g `SO_(2)`

Solution :`44g" of "CO_(2)=(44)/(44)"mole"="1 mole,"`
`"48 g of "O_(2)=(48)/(32)" mole"="1.5 mole"`
`8G H_(2)=(8)/(2)" mole = 4 mole,"`
`"64 g SO"_(2)=(64)/(64)" mole = 1 mole"`
1 mole of any gas contains AVOGADRO's no. of molecules


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