1.

Which has the maximum tendency to undergo E1 elimination ? (a) N-butyl bromide (b) Isobutyl bromide (c) Tertiary butyl bromide (d) Secondary butyl bromide

Answer» <p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option (c) Tertiary butyl bromide</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">E<sub>1</sub> elimination takes place via the formation of a stable carbonium ion which is possible from a tertiary alkyl halide only.</span></span></p>


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