Saved Bookmarks
| 1. |
Which is a stronger reducing agent `Cr^(2+)` or `Fe^(2+)` and why? |
|
Answer» (i). `Cr^(2+)(Z=24)=3d^54s^1,Cr^(2+)=3d^4,Cr^(3+)=3d^3` `Cr^(2+)toCr^(2+)+e^(ɵ)` (ii). `Fe(Z=36)=3d^64s^2,Fe^(2+)=3d^6,Fe^(3+)=3d^5` `Fe^(2+)toFe^(3+)+e^(ɵ)`. (Oxidation) (In a medium (like water) `d^3` is more stable as compared to `d^5`. |
|