1.

Which is cheaper : 40% hydrochloric acid at the rate of 50 paise per kilogram of 80%H_(2)SO_(4) at the rate of 25 paise per kilogram to completely neutralize 7 kg of caustic potash?

Answer»


SOLUTION :`underset(56kg)(KOH)+underset(36.5kg)(HCl)rarrKCl+H_(2)O`
`"PURE HCl required for 7 kg KOH "=(36.5)/(56)xx7=4.5625kj`
`40%" HCl acid required "=(100)/(40)xx4.5625=11.40625kg`
`"Cost "=11.40625xx50p=Rs.5.70p.`
`underset(2xx56kg)(2KOH)+underset(98kg)(H_(2)SO_(4))rarr K_(2)SO_(4)+2H_(2)O`
Proceed as above to calculate the cost of `80% H_(2)SO_(4).`


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