1.

Which is stronger reducing agent Cr^(2+) or Fe^(2 +)?

Answer»

Solution :`Cr^(2+)` and `Fe^(2 +)`
Cr (Z = 24) ELECTRONIC configuration-`[Ar] 3d^(5) 4s^(1)`
`Cr^(2+)`Electronic configuration-`[Ar] 3d^(4) 4s^(0)`
Fe (Z = 26)Electronic configuration-`[Ar] 3d^(6) 4s^(2)`
`Fe^(2+)` Electronic configuration-`[Ar] 3d^(6)4s^(0)`
If standard electrode potential (E) of a METAL is large and NEGATIVE, the metal is a powerful reducing agent.
`Cr^(2+)+ 2e^(-) to CrE^(0) = -0.91V`
`Fe^(2+) + 2e^(-) toFeE^(0) = -0.44 V`
By comparing the above equation, `Cr^(2+)` is a powerful reducing agent.


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