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Which is the actual configuration of Cr(Z=24).Why? |
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Answer» Solution :`Cr(z=24)1S^(2)2S^(2)2P^(6)3S^(2)3P^(6)3D^(5)4S^(1)` the reason for this is ,Cr with `3d^(5)` configuration is half filled and it will be more stable. Chromium has [Ar]`3d^(5)` `4s^(1)` and not [Ar]`3d^(4)4s^(2)` due to the symmetrical distribution and exchange energies of d electrons. |
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