Which is the correct sequence in the following properties? For the correct order mark (T) and for the incorrect order mark (F) : (i) Melting point : NH_(3) gt SbH_(3) gt AsH_(3) gt PH_(3) (ii) Boiling point : NH_(3) gt SbH_(3) gt AsH_(3) gt PH_(3) (iii) Dipole moment order : NH_(3) gt SbH_(3) gt AsH_(3) PH_(3)

Which is the correct sequence in the following properties? For the cor

1.	Which is the correct sequence in the following properties? For the correct order mark (T) and for the incorrect order mark (F) : (i) Melting point : NH_(3) gt SbH_(3) gt AsH_(3) gt PH_(3) (ii) Boiling point : NH_(3) gt SbH_(3) gt AsH_(3) gt PH_(3) (iii) Dipole moment order : NH_(3) gt SbH_(3) gt AsH_(3) PH_(3)
Answer» TFT FTF FFT FFT Solution :(i) (T), M.P of `NH_(3)` is HIGHEST due to INTERMOLECULAR H-bonding in it. Next lower M.P. will be of `SbH_(3)` followed by `AsH_(3)` due to high mol. Wt. of `SbH_(3)`. (II) (F), B.P. increase from `PH_(3) " to "SbH_(3) " via "AsH_(3)` due to increase in mol.wt. ` NH_(3)` does not follow this trend due to inter molecular H-bonding. Increasing B.P. order : `PH_(3) lt AsH_(3) lt NH_(3) lt SbH_(3)` (T) : VALUE of bond moment decreases.