1.

Which is the correct thermal stability order for H_2E (E = O, S, Se, Te, and Po) ?

Answer»

`H_(2)Se LT H_(2)Te lt H_(2)Po lt H_(2)O lt H_(2)S`
`H_(2)S lt H_(2)O lt H_(2)Se lt H_(2)Te lt H_(2)Po`
`H_(2)O lt H_(2)S lt H_(2)Se lt H_(2)Te lt H_(2)Po`
`H_(2)Po lt H_(2)Te lt H_(2)Se lt H_(2)S lt H_(2)O`

Solution :The REDUCING property the central ATOM INCREASES down the group due to decrease in bond dissociation enthalpy of E - H bond.


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