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Which method can be used to find out strength of reductant/oxidant in a solution ? Explain with an example. |
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Answer» Solution :STANDARD half cell potential connected with hydrogen ELECTRODE then measure of completely cell potential `(E_("cell")^(@))`. If value of `E_("cell")^(@)` is positive obtained then half cell acts as reducing agent if value of `E_("cell")^(@)` is negative then half cell as an oxidising agent. Using of this type of method calculate half cell potential of another cell. Then calculate strength of oxidising agent and reducing agent. Ex. We can calculate standard electrode potential of `Zn^(+2)//Zn` connected with hydrogen half cell. GIVEN, `E_("cell")^(@)=0.76"volt"` `E_("cell")^(@)=0.76=E_("cathode")^(@)-E_("anode")^(@)` `0.76=0-E_("anode")^(@)` `E_("anode")^(@)=-0.76"volt"` `E_(Zn^(+2)//Zn)^(@)=-0.76"volt"` |
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