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Which molecule/ion out or the following does not contain unpaired electrons ? |
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Answer» `N_(2)^(+` The ELECTRONIC CONFIGURATION of the given `N_(2)^(+) = sigma 1s^(2), sigma^(**) 1s^(2), sigma 2s^(2), sigma^(**) 2s^(2) , pi 2p_(x)^(2)= pi p_(y)^(2)sigma 2p_(Z)^(1)` It has ONE unpaired electron. `O_(2) = sigma 1s^(2), sigma^(**) 1s^(2) , sigma 2s^(2), sigma 2p_(z)^(2), pi 2p_(x)^(2) = pi 2p_(y)^(2) pi* 2p_(x)^(1), = pi** 2p_(y)^(1)` `O_(2)` has two unpaired ELECTRONS. `O_(2)^(2-) = sigma 1s^(2), sigma^(**)1s^(2), sigma 2s^(2), sigma^(**) 2s^(2), sigma 2p_(z)^(2), pi 2p_(x)^(2) = pi 2P_(y)^(2) pi ** 2p_(x)^(1) = pi ** 2p_(y)^(1)` So, `O_(2)^(2-)` has no unpaired electrons. `B_(2) = sigma 1s^(2), sigma^(**) 1s^(2), sigma 2s^(2), sigma^(**) 2s^(2) pi 2p_(x)^(1) = pi 2p_(y)^(1)` So`B_(2)` has two unpaired electrons. |
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