1.

Which of the followig inctruemnts has minium least count?

Answer»

A screw gauge of PITCH 1 mm and 100 divisions n the CIRCULAR scale.
A spherrrometer of pitch 0.1 mm and 100 divisions on the circular scale.
An optical intrument that can MEASURE length to within a wavelength of light.

Solution :Least count of vernier callipers
`=1MSD-1VSD=1MSD-(19)/(20)MSD`
`=(1)/(20)MSD=(1)/(20)mm=(1)/(200)cm=0.005cm`
(b) Least count of screw gauge
`=("Pitch")/("No. of divisions ono circular scale")`
`=(1)/(100)mm=(1)/(1000)cm=0.001m`
(c) Least count of spherometer
`=("Pitch")/("No. of divions on circular scale")`
`=(0.1mm)/(100)=(1)/(1000)mm=0.0001cm`
(d) Wavelength of light `lamda~~10^(-5)cm=0.00001cm`
CLEARLY the optical instrument is the most precise.


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