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Answer» a. `CH_(2)=CHCH_(3) ` b. `CH_(2)=CF_(2)` c.`CH_(2)=CHCN` d. `CH_(2)=CHC_(6)H_(5)` Solution :In anionic polymerisation , ( on reaction with `KNH_(2)`) carbanions are the intermediates. GREATER the STABILITY of the carbanion, more reactive is the alkene. Since the stability of the carbonions decreases in the order : `H_(2)N-CH_(2)-overset(-)CHCN gt H_(2)NCH_(2)overset(-)CF_(2) gt H_(2)NCH_(2)overset(-)CHC_(6)H_(5) gt H_(2)NCH_(2)overset(-)CHCH_(3)`, therefore , the REACTIVITY decreases in the same order . Thus `CH_(2)=CHCH_(3)` is least reactive.
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