1.

Which of the following aqueous solutions remains neutral after electrolysis ?

Answer»

`K_(2)SO_(4)`
`NaCl`
`AgNO_(3)`
`CuSO_(4)`

SOLUTION :Since reduction potential of `H_(2)Ogt` reduction potential of `K^(o+)` IONS, so the reduction of `H_(2)O` takes place, to give `H_(2)(g)`
Similarly, oxidation potential of `H_(2)Ogt` oxidation potential of `SO_(4)^(2-)` , so again the oxidation of `H_(2)O` TAKE place to give `O_(2)(g)`
Reduction of `H_(2)O` produces same equivalent of `overset(c-)(O)H` as the oxidation of `H_(2)O` produces same equivalent of `H^(o+)` ions to give neutral solution.
In option `(b), Na^(o+)` is not reducted, but `H_(2)O` is REDUCED to give `overset(c-)(O)H` ions. So solution is basic.
`Cl^(c-)` ions are oxidized at anode to give `Cl_(2)(g)`.
In option `(c)`, `Ag^(o+)` ions are reducted at cathode to give `Ag` , while `NO_(3)^(c-)` ions are not oxidized but `H_(2)O` is oxidized to give `H^(o+)` ions, so solution is acidic.
In option `(d), Cu^(2+)` ions are reduced at cathode to give `Cu`, while `SO_(4)^(2-)` ions are not oxidized, but `H_(2)O` is oxidized to give `H^(o+)` ions, so solution is acidic.


Discussion

No Comment Found