InterviewSolution
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InterviewSolution
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Which of the following arrangements represent the correct order of the property stated against it ? (i) `Ni^(2+) lt Co^(2+) lt Fe^(2+) lt Mn^(2+)` : ionic size (ii) `Co^(3+) lt Fe^(3+) lt Cr^(3+) lt Sc^(3+)` : stability in aqueious solution (iii) `Sc lt Ti lt Cr lt Mn` : number of oxidation states (iv) `V^(2+) lt Cr^(2+) lt Mn^(2+) lt Fe^(2+)` : paramagnetic behaviourA. Sc gt Ti gt Cr lt Mn : number of oxidation statesB. `V^(2+) ltCr^(2+) ltMn^(2+) ltFe^(2+)` : paramagnetic behaviourC. `Ni^(2+) lt Co^(2+) ltFe^(2+) ltMn^(2+)` : ionic sizeD. `Co^(3+) lt Fe^(3+) lt Cr^(3+) lt Sc^(3+)` : stability in aqueous solution. |
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Answer» Correct Answer - B Number of unpaired electrons in `Fe^(2+)` is less than `Mn^(2+)`, so `Fe^(2+)` is less paramagnetic than `Mn^(2+)`. |
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