InterviewSolution
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InterviewSolution
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Which of the following cannot be valid assignment of probability for elementary events or outcomes of sample space S = {w1, w2, w3, w4, w5, w6, w7}:Elementary eventsW1W2W3W4W5W6W7(i)0.10.010.050.030.010.20.6(ii)\(\frac{1}{7}\)\(\frac{1}{7}\)\(\frac{1}{7}\)\(\frac{1}{7}\)\(\frac{1}{7}\)\(\frac{1}{7}\)\(\frac{1}{7}\)(iii)0.70.60.50.40.30.20.1(iv)\(\frac{1}{14}\)\(\frac{2}{14}\)\(\frac{3}{14}\)\(\frac{4}{14}\)\(\frac{5}{14}\)\(\frac{6}{14}\)\(\frac{15}{14}\) |
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Answer» For each event to be a valid assignment of probability, the probability of each event in sample space should be less than 1 and the sum of probability of all the events should be exactly equal to 1 (i) it is valid as each P(wi) (for i=1 to 7) lies between 0 to 1 and sum of P(w1) = 1 (ii) it is valid as each P(wi) (for i = 1 to 7) lies between 0 to 1 and sum of P(w1) =1 (iii) it is not valid as sum of P(wi)=2.8 which is greater than 1 (iv) it is not valid as P(w7) = \(\frac{15}{14}\) which is greater than 1. |
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