1.

Which of the following complex exhibits the highest paramagnetic behaviour ? where gly = glycine, en = ethylene diamine and bpy = bipyridyl moities (At Nos. Ti = 22, V = 23, Fe = 26, Co = 27)

Answer»

`[V(gly)_(2)(OH)_(2)(NH_(3))_(2)]^(+)`
`[Fe(en)(bpy)(NH_(3))_(2)]^(2+)`
`[Co(OX)_(2)(OH)_(2)]^(2-)`
`[Ti(NH_(3))_(6)]^(3+)`

Solution :Ox. State of Vin (a) :
x+2(-1)+2(-1)+0=+1 or x=+5
`THEREFORE` Valence SHELL config. = `3d^(0)` (i.e., no unpaired ELECTRON)
Ox state of Fe in (b) : x+0+0+0=+2
or x = + 2
`therefore` Valence shell config. = `3d^(6)` (i.e., 4 unpaired electrons)
Ox. state of Co in (c ) : x+2(-2)+2(-1)=-2
or x=+4
`therefore` Valence shell config. `=3d^(5)` (i.e., 5 unpaired electrons)
Ox state of Tiin (d) : x+6(0)=+3 or x=+3
`therefore` Valence shell config. = `3d^(1)` (i.e., 1 unpaired electron)
THUS, complex of cobalt has MAXIMUM unpaired electrons (viz. 5) and hence has highest paramagnetism.


Discussion

No Comment Found