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Answer» `[Co(en)_(3)]CI_(3)` `[Co(en)_(2)CI_(2)]CI` `[Co(PPh_(3))_(2)(NH_(3))CI_(2)]CI` `[Co(PPh_(3))_(3)CI]CI_(2)` Solution :Complex (1) exhibits optical isomerism and thus exits in TWO enantomeris form. Complex exhibits geometrical as well as optical isomerism. The cis - form is OPTICALLY ACTIVE. Thus, there are THREE isome: `(+)` - cis, `(-)` - cis andtrans - form. Complex (3) being squar planar exhibits only geomertrical isomerism. Thus, it exists in two forms: cis- and trans. Complex (4) exhibits no isomerism. Thus, the maximum no. of isomers are of complex (2).
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