1.

Which of the following compounds is resolvable ? .

Answer»

`CH_(3)CH_(2)CH_(2)CH(CH_(3))NH_(2)`
`[CH_(2)=CHCH_(2)underset(Ph)underset(|)(N)(CH_(3))(CH_(2)H_(5))]^(+)I^(-)`

All of these

Solution :In the first compound the chirality is due to the presence of the chiral `2^(@)` penty1 carbon chain In the second compound N atom uses `sp^(3)` hybridized orbital to from four sigma bonds to four different LIGANDS The resulting cationic enantiomers are configurationally stable at ROOM temperature because there is no lone PAIR to permit N inversion In the third compound N inversion requires too high energy of activation because the N in such a small ring cannot attain the `120^(@)` angles required in the TS .


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