1.

Which of the following compounds is square planar and does have any unpaired electron?

Answer»

`NI(CO)_(4)`
`[Ni(H_(2)O)_(6)]^(2+)`
`[NiCl_(4)]^(2-)`
`[Ni(CN)_(4)]^(2-)`

Solution :`[Ni(CN)_(4)]^(2-)`

Therefore, hybridisation is `DSP^(2)`, structure is square plnar and it is diamagnetic.


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