1.

Which of the following compounds will not exist as resonance hybrid? Give reason for your answer. (a) CH_(3)OH (b) R- CONH_(2) (c ) CH_(3)CH= CHCH_(2)NH_(2)

Answer»

SOLUTION :(a) `CH_(3)OH` does not contain `pi`-electron and hence it cannot be regarded as a resonance hybrid.
(b) The COMPLETE structure of `R- CONH_(2)` is as under

In this 1-(lone pair), 2- (`pi`-electron), 3-single bond and 4 nonbonding p electron on N and alternate `pi` bond system is PRESENT so following rsonance structure can be expressed

`therefore` (b) `RCONH_(2)` has POSSIBLE resonance structure.
(c ) In this alteranate `pi//p` ELECTRONS are not there and C=C has more than one singma bond. So in C resonance is not possible.


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