Which of the following compounds will not exist as resonance hybrid. Give reason for your answer : (i) CH_(3)OH (ii) R-CONH_(2) (iii) CH_(3)CH=CHCH_(2)NH_(2)

Which of the following compounds will not exist as resonance hybrid. G

1.	Which of the following compounds will not exist as resonance hybrid. Give reason for your answer : (i) CH_(3)OH (ii) R-CONH_(2) (iii) CH_(3)CH=CHCH_(2)NH_(2)
Answer» Solution :(i) `CH_(3)-OH` does not contain `pi`-electrons and HENCE it cannot be regarded as a resonance hybrid. (II) Due to the presence of `pi`-electrons in C = O bond and n-electrons on N, amide can be represented as a resonance hybrid of the following THREE resonating structures. (iii) Since the lone pair of electrons on the N atom is not conjugated with the `pi`-electrons of the double bond, therefore, resonance is not possible. `CH_(3)-CH = CH - CH_(2) - overset(..)(N)H_(2)` Resonance not possible.