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Answer» `t_(2g)^(6)e_(g)^(1)`
`t_(2g)^(6)e_(g)^(2)`
`t_(2g)^(6)e_(g)^(4)`
`t_(2g)^(6)e_(g)^(0)` Solution :Repulsion by six ligands in an octahedral complex splits the d-orbitals on the central atom into `t_(2g)` and `e_(g)` levels. It follows that there is a corresponding repulsion between the d-electrons and the ligands . If the d-electrons are symmetrically ARRANGED, they will repel all six ligands EQUALLY. THUS the STRUCTURE will be REGULAR octahedron. If the d-electrons are asymmetrically arranged, they will repel some ligands in the complex more than others. Thus the structure is distorted. Out of the given options, symmetrical arrangements are `: (b) t_(2g) ^(6) e_(g)^(2)` (c )`t_(2g)^(6)e_(g)^(4)` (d)`t_(2g)^(6) e_(g)^(0)` unsymmetrical arrangement is `: (a) t_(2g)^(6) e_(g)^(1)`
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