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Which of the following contains same number of carbon atoms as are in 6.0g of carbon (C-12)? |
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Answer» 6.0 g ETHANE `C_(2)H_(6)` = molar mass = 24 + 6 = 30g 30 g of ethane CONTAINS `2xx6.023xx10^(23)` Carbon atoms. (b) 8.0 g of methane (`CH_(4)` ) `CH_(4)` = molar mass = 12 + 4 = 16 g 16 g of methane contains `6.023xx 10^(23)` Carbon atoms. (c) 21.0 g of propane (`C_(3)H_(8)` ) `C_(3)H_(8)` = molar mass = 36 + 8 = 44 g 44 g of propane contains `3 xx6.023xx 10^(23)` Carbon atoms. (d) 28.0 g of Carbon monoxide (CO) CO = molar mass = 12 + 16 = 28 g 28 g of Carbon monoxide contains `6.023xx 10^(23)` Carbon atoms. 6.0 g of Carbon contains `(6.023xx10^(23))/12xx 6 = 3.0115xx10^(23)` Carbon atoms. Among the (a), (b), (c), (d)-8g g of `CH_(4)` contains `(6.022xx10^(23))/16xx8` `=3.0115xx10^(23)`carbon atoms |
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